(x+2x^3-3)/(x-1)=0

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Solution for (x+2x^3-3)/(x-1)=0 equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(2*x^3+x-3)/(x-1) = 0

2*x^3+x-3 = 0

2*x^3+x-3 = 0

{ 1, -1, 3, -3 }

1

x = 1

2*x^3+x-3 = 0

1

x-1

2*x^2+2*x+3

2*x^3+x-3

x-1

2*x^2-2*x^3

2*x^2+x-3

2*x-2*x^2

3*x-3

3-3*x

0

2*x^2+2*x+3 = 0

DELTA = 2^2-(2*3*4)

DELTA = -20

DELTA < 0

x in { 1} 

x-1 = 0

1 = 0

x belongs to the empty set

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